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a 2100kg truck traveling north at 41 km/h turns east and accelerates to 51 km/h. What is the change in the truck's kinetic energy?
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KE = 0.5 m x v x v
yes i tried doing that i converted the speeds to M/S and then did 1/2MV^2-1/2mv^2 and got 90,000j but the answer is 75,000 j
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