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Explain how to solve x^2 + 8x by completing the square.
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an equation of the type ax^2+bx to solve it add and subtract (-1/2)*Coefficient of x to this equation
x^2+8x+16-16 (x+4)^2-16
wait you added 16 and then took it out?
ya...........you need to add as well as subtract
then what happens to the 8x?
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see -(1/2) *coefficient of x -(1/2)*(8) -4 square it 16 add and subtract to the given equation ie. x^+8x+16-16 (x^2+8x+16)-16 (x+4)^2-16
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