Question

Please help:)
write a java program that reads two integers as start and last. within that ranges, it should differentiate ODD values and EVEN values and display the separated list on screen with the sum of ODD and sum of EVEN. the program will be repeated until the termination condition is given by the user(Hint:if both start and last integer are equal then the program will terminate)

Answer 1

This is vat I hav done so far.
import java.io.*;
public class Problem_a
{
public static void main(String[]args) throws IOException
{
BufferedReader keyboard=new BufferedReader
(new InputStreamReader(System.in));
int a_1;//First term
int a_n;//Last term
int n;//Number of odd and even numbers available within the range
int odd;
int even;
int sum_1=0;//Sum of odd numbers
int sum_2=0;//sum of even numbers
System.out.print("Enter the first number:");
a_1=Integer.parseInt(keyboard.readLine());
System.out.print("Enter the last number:");
a_n=Integer.parseInt(keyboard.readLine());
n=((a_n-a_1)/2)+1;
if(((a_1%2==1) && (a_n%2==0)) || ((a_1%2==0) && (a_n%2==1)))
{
for(int i=1;i<=n;i++)
{
odd=a_1+((i-1)*2);
System.out.print(" "+odd+" ");
sum_1+=odd;
}
System.out.print("\n");
System.out.println(sum_1);
for(int j=1;j<=n;j++)
{
even=(a_1+((j-1)*2))+1;
System.out.print(" "+even+" ");
sum_2+=even;
}
System.out.print("\n");
System.out.print(sum_2);
}
else if(a_1%2==1 && a_n%2==1)
{
for(int i=1;i<=n;i++)
{
odd=a_1+((i-1)*2);
System.out.print(" "+odd+" ");
sum_1+=odd;
}
System.out.print("\n");
System.out.println(sum_1);
for(int j=1;j<n;j++)
{
even=(a_1+((j-1)*2))+1;
System.out.print(" "+even+" ");
sum_2+=even;
}
System.out.print("\n");
System.out.print(sum_2);
}
else
{
for(int i=1;i<n;i++)
{
odd=a_1+((i-1)*2);
System.out.print(" "+odd+" ");
sum_1+=odd;
}
System.out.print("\n");
System.out.println(sum_1);
for(int j=1;j<n;j++)
{
even=(a_1+((j-1)*2))+1;
System.out.print(" "+even+" ");
sum_2+=even;
}
System.out.print("\n");
System.out.print(sum_2);
}
}
}

Answer 2

@Chris2332 please help me:)

Answer 3

@eSpeX please help.

Answer 4

Sorry, computer stuff is out of my range of expertise.

Answer 5

That's k. Thanx a lot for taking a look.:)

Answer 6

what are you looking for? be concise ...

Answer 7

ah ... my bad. I don't have jdk installed ... hold on for few min.

Answer 8

oh k:)

Answer 9

I don't have fast connection ... perhaps it would take more than half hour ... can you summmarize what are you trying to do. I haven't programmed java for quite a long time.

Answer 10

I need to display the odd numbers and the even numbers between two numbers and also their sum seperately. When I compile the above program the output comes right. bt i have to include a condition that the program will be repeated until the termination condition is given by the user(Hint:if both start and last integer are equal then the program will terminate)

Answer 11

I hav no idea what that condition will be.

Answer 12

why not wrap the whole program in while loop?

Answer 13

or ... set the condition true ... inside while loop.
use
if start == final ... break; inside while loop.

Answer 14

hope this part is correct
int sum_1=0;//Sum of odd numbers
int sum_2=0;//sum of even numbers
System.out.print("Enter the first number:");
a_1=Integer.parseInt(keyboard.readLine());
System.out.print("Enter the last number:");
a_n=Integer.parseInt(keyboard.readLine());
n=((a_n-a_1)/2)+1;
if(((a_1%2==1) && (a_n%2==0)) || ((a_1%2==0) && (a_n%2==1)))
{
for(int i=1;i<=n;i++)
{
odd=a_1+((i-1)*2);
System.out.print(" "+odd+" ");
sum_1+=odd;
}
System.out.print("\n");
System.out.println(sum_1);
for(int j=1;j<=n;j++)
{
even=(a_1+((j-1)*2))+1;
System.out.print(" "+even+" ");
sum_2+=even;
}
System.out.print("\n");
System.out.print(sum_2);
}
else if(a_1%2==1 && a_n%2==1)
{
for(int i=1;i<=n;i++)
{
odd=a_1+((i-1)*2);
System.out.print(" "+odd+" ");
sum_1+=odd;
}
System.out.print("\n");
System.out.println(sum_1);
for(int j=1;j<n;j++)
{
even=(a_1+((j-1)*2))+1;
System.out.print(" "+even+" ");
sum_2+=even;
}
System.out.print("\n");
System.out.print(sum_2);
}
else
{
for(int i=1;i<n;i++)
{
odd=a_1+((i-1)*2);
System.out.print(" "+odd+" ");
sum_1+=odd;
}
System.out.print("\n");
System.out.println(sum_1);
for(int j=1;j<n;j++)
{
even=(a_1+((j-1)*2))+1;
System.out.print(" "+even+" ");
sum_2+=even;
}
System.out.print("\n");
System.out.print(sum_2);
}

Answer 15

while(true)
{

// first of all input the integers
if start == final
break;

}

rewrite that whole thing inside this loop.

Answer 16

gotta go out for a while ... brb in an hour.

Answer 17

ha k. Thanx a lot:)

Answer 18

import java.io.*;
public class Problem_a
{
public static void main(String[]args) throws IOException
{
BufferedReader keyboard=new BufferedReader
(new InputStreamReader(System.in));
int a_1;//First term
int a_n;//Last term
int n;//Number of odd and even numbers available within the range
int odd;
int even;
int sum_1=0;//Sum of odd numbers
int sum_2=0;//sum of even numbers
while(true)
{
System.out.print("Enter the first number:");
a_1=Integer.parseInt(keyboard.readLine());
System.out.print("Enter the last number:");
a_n=Integer.parseInt(keyboard.readLine());
n=((a_n-a_1)/2)+1;
if(((a_1%2==1) && (a_n%2==0)) || ((a_1%2==0) && (a_n%2==1)))
{
for(int i=1;i<=n;i++)
{
odd=a_1+((i-1)*2);
System.out.print(" "+odd+" ");
sum_1+=odd;
}
System.out.print("\n");
System.out.println(sum_1);
for(int j=1;j<=n;j++)
{
even=(a_1+((j-1)*2))+1;
System.out.print(" "+even+" ");
sum_2+=even;
}
System.out.print("\n");
System.out.print(sum_2);
}
else if(a_1%2==1 && a_n%2==1)
{
for(int i=1;i<=n;i++)
{
odd=a_1+((i-1)*2);
System.out.print(" "+odd+" ");
sum_1+=odd;
}
System.out.print("\n");
System.out.println(sum_1);
for(int j=1;j<n;j++)
{
even=(a_1+((j-1)*2))+1;
System.out.print(" "+even+" ");
sum_2+=even;
}
System.out.print("\n");
System.out.print(sum_2);
}
else
{
for(int i=1;i<n;i++)
{
odd=a_1+((i-1)*2);
System.out.print(" "+odd+" ");
sum_1+=odd;
}
System.out.print("\n");
System.out.println(sum_1);
for(int j=1;j<n;j++)
{
even=(a_1+((j-1)*2))+1;
System.out.print(" "+even+" ");
sum_2+=even;
}
System.out.print("\n");
System.out.print(sum_2);
}
if (a_1 == a_n)
{
break;
}
}
}
}
This is hw it comes right when I include while loop like u said?
If I give the same value for first and last it displays the sums of previously done ones. How do I edit it?

Answer 19

seems it is working

Answer 20

put this thing right after you input it
if (a_1 == a_n)
{
break;
}

Answer 21

import java.io.*;
public class Test
{
public static void main(String[]args) throws IOException
{
BufferedReader keyboard=new BufferedReader
(new InputStreamReader(System.in));
int a_1;//First term
int a_n;//Last term
int n;//Number of odd and even numbers available within the range
int odd;
int even;
int sum_1=0;//Sum of odd numbers
int sum_2=0;//sum of even numbers
while(true)
{
System.out.print("Enter the first number:");
a_1=Integer.parseInt(keyboard.readLine());
System.out.print("Enter the last number:");
a_n=Integer.parseInt(keyboard.readLine());
if (a_1 == a_n)
{
break;
}
n=((a_n-a_1)/2)+1;
if(((a_1%2==1) && (a_n%2==0)) || ((a_1%2==0) && (a_n%2==1)))
{
for(int i=1;i<=n;i++)
{
odd=a_1+((i-1)*2);
System.out.print(" "+odd+" ");
sum_1+=odd;
}
System.out.print("\n");
System.out.println(sum_1);
for(int j=1;j<=n;j++)
{
even=(a_1+((j-1)*2))+1;
System.out.print(" "+even+" ");
sum_2+=even;
}
System.out.print("\n");
System.out.print(sum_2);
}
else if(a_1%2==1 && a_n%2==1)
{
for(int i=1;i<=n;i++)
{
odd=a_1+((i-1)*2);
System.out.print(" "+odd+" ");
sum_1+=odd;
}
System.out.print("\n");
System.out.println(sum_1);
for(int j=1;j<n;j++)
{
even=(a_1+((j-1)*2))+1;
System.out.print(" "+even+" ");
sum_2+=even;
}
System.out.print("\n");
System.out.print(sum_2);
}
else
{
for(int i=1;i<n;i++)
{
odd=a_1+((i-1)*2);
System.out.print(" "+odd+" ");
sum_1+=odd;
}
System.out.print("\n");
System.out.println(sum_1);
for(int j=1;j<n;j++)
{
even=(a_1+((j-1)*2))+1;
System.out.print(" "+even+" ");
sum_2+=even;
}
System.out.print("\n");
System.out.print(sum_2);
}
}
}
}

Answer 22

Ya it works perfectly nw:D. Thank u sooooooooooo much.:D That was a bigg help.