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Solve the following equations for all solutions of x sec^2x-2tanx=4
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Sec^2 = 1 + Tan^2
So do I substitute that in for sec^2? Like...tan^2-2tanx=3?
Yup, now u have a quadratic in Tan....(let Tan = x)
So should I make it equal zero by taking away 3?
Yes...it factors easily, then just solve it like any normal equation.
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I came up with 3,-1??
I don't understand....?
If I factor out as (tan-3)(tan+1)=0?? Am I on the right track?
Yes.
And then if I say... tan-3=0 tan+1=0 I get 3,-1? Is that correct?
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