plot the graph of y=2x2+7x-4? Thanks before that :)
@sheldonEinstein
you should be able to determine at most, 4 points that will help define this in a unique manner and make a sketch of the graph.
y intercept x intecepts (0, 1, or 2) vertex
if the intent is to plot all the points, then you will simply need to make a table of values; which is very time consuming
amistre64: Can you help me to draw the graph?
yes, we would need to determine the points that i listed
when x=0, the y intercept (the value of y) is what?
@amistre64 can you help me to draw the graph? and how about the vertex and y intercept
sorry, but the OpenStudy is playing tricks with my computer.
@amistre64 how about the value of vetex and y intercept?
y intercept is when x = 0 vertex uses the form -b/2a ; or simply find the center between the zeros
you can restructure the equation by "completing the square" to reform it into the vertex form; or simply use the -b/2a to define the y value
if you know the quadraticv formula, you can even pull off the zeros\[x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\]
@amistre64 ok, thanks
youre welcome if you want to check your graph sketch, the wolf is pretty good at it
@SheldonEinstein
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