Question

Can someone help me solve:
3(x-2)^2/4=24

Answer 1

is it
\[\frac{3(x-2)^2}{4}=24\]?

Answer 2

if so, start with
\[(x-2)^2=24\times \frac{4}{3}\]
\[(x-2)^2=32\] and then it should be straighforward
take the square root,
don't forget the \(\pm\)
then add two