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Algebra
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Amy is twice as old as jenny. five years ago, amy was three times as old as jenny. find jenny's age.
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Let's first find variables for Amy and Jenny. A = Amy J = Jenny
Ohhkaay
A = 2J so A - 2J = 0 A - 5 = 3(J - 5) A - 5 = 3J - 15 + 5 A - 3J = - 10 Since A - 2J = 0 A - 3J = -10 So -J = -10; therefore, J = 10 Now we've found that Jenny is ten, and since Amy is twice as old: Jenny = 10, Amy = 20
i get it now thanks
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