how do i solve the systems 2m + 4n = 10
3m + 5n = 11
and
5x + y = 0
5x + 2y = 30
using elimination?

Question

how do i solve the systems 2m + 4n =  10
                                             3m + 5n = 11
and
   5x + y = 0
   5x + 2y = 30
using elimination?

anonymous · Answer

2m + 4n =  10        -- (I)
3m + 5n = 11         -- (II)

Multiply (I) by 3 and (II) by  -2 nd then add the resulting equations.  This way m will be eliminated and the remaining equation will give value of n.

Then put this value of n in either (I) or (II) and get the value of m

anonymous · Answer

5x + y = 0             --(I)
 5x + 2y = 30        --(II)

Multiply (I) by 1 and (II) by -1 and add.  x will be eliminated and from the resulting equation you can find the value of y.  Then put that value in either (I) or (II) and get the value of x