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f(x)=log base 3 (2x) Find the inverse function of f!
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inverse of log is exponential, in this case you base it 3
we can put \(x=\log_3(2y)\) and solve for \(y\) if you like that method first step would be \[3^x=2y\] then you are done in one more step
jeez i can't type "in this case your base is three" is what i meant to write
Okay, I'm following, what's the last step?
divide by 2!
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oh duh, thanks so much, again! :)
yw
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