Question

p(a)=.05a t(p)=3p t(a)=?

Answer 1

please be more detailed while posting questions.

Answer 2

the variables are just variables, they don't mean anything...

Answer 3

\[p(a)=0.05a\]\[t(p)=3p\]
Then \[t(a)=(3)(0.05a)\]\[t(a)=0.15a\]

Answer 4

How do you know how to combine the functions?

Answer 5

t(p)=3p

t(1) = 3*1 = 3

t(2) = 3*2 = 6

t(a) = 3*a = 3a

Answer 6

To be More Specific:

f(x) = 2x + 3

f(1) = 2+3

f(a) = 2a + 3

Answer 7

You haven't given us any info to say not to.. So my assumption is that p(a)=0.05a is the function way of writing p=0.05a. Therefore you can substitute that into t(p) to get \[t(a)=3(0.05a)=0.15a\]

Answer 8

@stardust3829 DId u get my point

Answer 9

but @Yahoo! also has a point. Because of the lack of information this can be interpreted in different ways.

Answer 10

not really, a little bit, but not much :) sorry

Answer 11

how does knowing what the functions are saying, help to know how to combine them?

Answer 12

You've given us two functions and you want us to find a third function which returns the same variable as one of the functions but takes a different input. <<<--- confusing sentence.

y=2x is the same as y(x)=2x. x being your input and y your output.
now if you had say h=5y. that's the same as saying h(y)=5y... with y as your input and h your output.
Now you want to find h(x). which has an input of x but an output of y. so from that you know you nee to combine the equations.
you get h(y)=h(2x) and since your h=5y.. y the input. you get h(2x)=5(2x).
but you want it as h(x). so you simplify the right side 5(2x)=10x.. and now your h=10x, which is the same as h(x)=10x

Answer 13

thank you