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Discrete Math 13 Online
OpenStudy (lgbasallote):

What is the converse of the implication "If |x| = x, then x >= 0"

OpenStudy (lgbasallote):

it would be if x > =0 then |x| = x yes?

OpenStudy (anonymous):

if \[\left| x \right|=x,then x <, 0\]

OpenStudy (lgbasallote):

isn't that inverse?

OpenStudy (lgbasallote):

wait..no...it isn't...

OpenStudy (lgbasallote):

i don't know what kind of statement that is...

OpenStudy (lgbasallote):

if p then not q

OpenStudy (phoenixfire):

No, @lgbasallote is right. \[P \rightarrow Q\] converse is \[Q \rightarrow P\]

OpenStudy (lgbasallote):

wonderful

OpenStudy (anonymous):

excuse me ,sorry for the confusion

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