Question

Calculus: Find the derivative.
y=4x/squareroot(2x-1)

Answer 1

\[\frac{ 4x }{ \sqrt{2x-1} }\]

Answer 2

u knw Quotient rule...!!

Answer 3

low d high - high d low

Answer 4

Hint: \[\sqrt{2x-1}= (2x-1)^{\frac{ 1 }{ 2 }}\]

Answer 5

yeah i know how to do these its just that i mite have made a mistake :\

Answer 6

the answer is \[\frac{ 4x-4 }{ (2x-1)_{2}^{3} }\]

Answer 7

but i got \[\frac{ 12x-4 }{ (2x-1)_{2}^{3} }\]

Answer 8

when i used quotient rule :)