Question

a[]={0,1,2,3,4,5,6,7,8,9,10};
i=0;
a[i]=a[++i+a[++i]]+a[++i];
cout< 13 years ago

Answer 1

cout<<a[9]; //if u output 9

Answer 2

ans is 9

Answer 3

yes,

Answer 4

i know ans is 9 how it came(evaluated)?

Answer 5

This is a test of your understanding of order of operations.

At std::cout you should see that i == 3.
What is a[ 3 + a[3]] + a[3]?

Answer 6

i evaluated like a[1+a[2]]+a[3];
tell me the logic of 3 at all places

Answer 7

++i is evaluated first, so the function is:

a[ 3 + a[3]] + a[3]
not
a[1+a[2]]+a[3]

thus
a[ 3 + a[3]] + a[3] == a[3 +3] + 3
== a[6] + 3
== 6 + 3
== 9