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0<-8b<12 Solve compound Inequality PLEASE THIS IS DUE TODAY !
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divide each side by -8, so you get (0/-8) <b<(12/-8)
iS THAT THE ASNWER ?
should be 0<b<(-3/2)
divide by \(-8\) and flip the inequalities because \(-8\) is negative
no
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there is no such number for one thing for another, you have to change the inequalities when dividing by a negative number \[0<-/b<12\iff \frac{8}{-8}>b>\frac{12}{-8}\]
Am really sorry but I only need the answer and how to do it this is due in an hour so please I need the answer and steps how to get it I know it sounds rude and bad but I don't get any of thsi
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