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6x - 14 = 6x - 14? D:
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If you could show me how you solved it, that'd be awesome. ._.
Hey, long time haven't seen ya here.
I KNOW RIGHT? I fell off the planet. xD
And this is some axiom: If blah = blah then all real numbers are included in the solution.
..o.o so how would I solve for x then?
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Hmm, if you like the non-layman's language, then:\[\rm \large f(x) = f(x) \qquad \implies \qquad x = x\]
If you really wanna show it, then add 14 to both sides and then divide both by 6.
Oh wait, I was reading the question associated with the problem wrong, haha. xD GOT IT. (x
lol
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