Question

Write the equation of the line that is parallel to the line 4x − 3y = −12 and passes through the point (−3, 4).

y = four thirdsx + 8

y = four thirdsx + 3

y = −three fourthsx + 8

y = −three fourthsx + 3

Answer 1

4x-3y=-12

-3y=-4x-12
y=4/3x+4

Slope= 4/3 and remember parallel=same slope

y=mx+b , m=4/3 , (-3,4)

4=4/3(-3)+b
4=-4+b
8=b

=> y=4/3x+8

Answer 2

THNK SO MUCH:)

Answer 3

YOU'RE WELCOME :)

Answer 4

CAN U HELP ME WITH ANOTHR ONE PLZ??

Answer 5

YES!

Answer 6

Write the equation of the line that is perpendicular to the line 3x + y = 7 and passes through the point (6, −1).

y = one thirdx − 3

y = one thirdx + 17

y = −3x − 3

y = −3x + 17

Answer 7

m=1/3 , (6,-1)

y=mx+b
-1=1/3(6)+b
-1=2+b
-3=b

=> y=1/3x-3

Answer 8

thank you:)

Answer 9

No problem :)