Question

1/2x-1/3y+z=1
x-y+z=-2
x+2/3z=0 i only need help finding y, thanks!!!

Answer 1

so than there are

x/2 -y/3 +z =1
x-y+z=-2
x+2z/3=0 so here have not y ?

Answer 2

wouldnt equation c be plugged into equations and b

Answer 3

* a and b

Answer 4

but real in 3rd have not y ?

Answer 5

or you have missed it ?

Answer 6

no, i thought you would change it to x=2/3x+0

Answer 7

1/2(2/3x+0)-1/3y+z=1

Answer 8

thts equation a

Answer 9

please first of all rewrite me please your exercise correct

ok ?

Answer 10

it is correct

Answer 11

so than in the 3rd equation have not y

yes ?

Answer 12

it doesnt have y

Answer 13

ok

Answer 14

x/2 -y/3 +z=1 so what will be here the common denominator for you can assum these fractions ?

Answer 15

yes,

Answer 16

can you assuming these fractions ?

Answer 17

wait

Answer 18

then...?