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Linear Algebra
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can someone help me out please with these questions please:1;find a general lineal equation (Ax+By+C=0) of the straight line that has the indicated properties,and sketck each line please. 1;PASSes through(-5,5) and has slope of -1/2. 2:sasses through(-3,-4)and(-2,-8). 3:is a vertical and passes through(-1,-1).
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1) you have the slope with a point on the line, thus the equation of the line is \[\frac{ y-5 }{ x-(-5) }=\frac{ -1 }{ 2 }\]\[=2y-10=-x-5\]\[=2y+x-5=0\]
2) you have two points that are on the line, thus \[\frac{ y-(-4) }{ x-(-3) }=\frac{ -8-(-4) }{ -2-(-3) }\]then simplify it.
3) For any vertical line that pass through a point (a, b), the equation of the line will be\[x=a\]thus the answer here is \[\Huge x=-1\]
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