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Given triangle ABC is equiangular and segment EF is parallel to segment AC, prove triangle EFB is equiganular
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|dw:1351226156783:dw| Because the segments are parallel, the sides AB and AC are transversals; and certain angles are congruent when parallel lines are cut by a transversal.
so because EF is parallel with AC so hence angle F is congruent angle C and angle E congruent angle A so angle B si angle common so than result triangle ABC is similar with triangle EFB
Yes.
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