5 kg of water is heated from 20 C to 90 C (293 and 327 K). The density of the water decreases from 998,3 kg/m^3 to 965 kr/m^3.

How much pressure-volume work is done by the system?

I think I'm supposed to use the formula:

W = p * dV

V (volume) = (5/965) - (5/998,3)

But how do I get pressure? That would seem to require the dimensions of the water, which I don't have. Or maybe I'm using the wrong formula?

Question

5 kg of water is heated from 20 C to 90 C (293 and 327 K). The density of the water decreases from 998,3 kg/m^3 to 965 kr/m^3.

How much pressure-volume work is done by the system?

I think I'm supposed to use the formula:

W = p * dV

V (volume) = (5/965) - (5/998,3)

But how do I get pressure? That would seem to require the dimensions of the water, which I don't have. Or maybe I'm using the wrong formula?

anonymous · Answer

dimensions of water mean??