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Precalculus
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prove the identity. show all work. cos(x-pi/2)=sin x
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cos (A+B) = ?
huh?
cos (A+B) =cos A cos B - sin A sin B now put A=x and B=pi/2
but its cos (x-pi/2) not addition?
sorry, B = -pi/2 or u can use cos (A-B) = cos A cos B +sin A sin B
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ohh ok so cos xcospi/2+sin x cospi/2
cos x cos pi/2+sin x sin pi/2 now what is cos pi/2 and sin pi/2 = ?
0
sin =1
so plug those values in, what u get ?
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so the rhs cancels ans ur left with 1 *sin x which is equal to sinx
thats correct :)
cos x cos pi/2+sin x sin pi/2 = cos x (0)+sin x (1) = sin x
yay thank you only a few more questions and im done
great ! bring it on ...
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