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OpenStudy (anonymous):
How do you put, (y-2)/3=x into the form of y=mx+c???
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OpenStudy (anonymous):
multiply both side of the equation by 3 giving y-2 = 3x next add 2 to both sides giving y = 3x + 2
OpenStudy (anonymous):
Y=x/3-2
OpenStudy (anonymous):
Thankyou :)
OpenStudy (tasreeb):
Y-2/3=X Y-2=3X Y=3X+2, m=3nd c=2
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