Mathematics
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OpenStudy (anonymous):
the perimeter of a rectangle is 78m.the width is 7m less than the length. find the length AND width.
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jhonyy9 (jhonyy9):
P=2l+2w
and you know again that w=l-7
now hope you will can calcule it easy ,yes ?
OpenStudy (anonymous):
not exactly, but i got so far this...hang on
jhonyy9 (jhonyy9):
@AriPotta hope you can calcule it for medal ,ok ?
OpenStudy (anonymous):
78=2(l-7)+2l
782l-14+2l
78+14=92
92=4l
OpenStudy (aripotta):
that's right, just divide both sides by four to get the answer for l
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OpenStudy (anonymous):
78=2(l-7)+2l
78=2l-14+2l
78+14=92
92=4l
OpenStudy (anonymous):
sorry had a mistype
OpenStudy (anonymous):
which side of what?
OpenStudy (aripotta):
92 = 4l
OpenStudy (aripotta):
when you divide both sides by four, what do you get?
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OpenStudy (anonymous):
88=L
OpenStudy (anonymous):
wait no i subtratcred
OpenStudy (aripotta):
yea, you gotta divide lol
OpenStudy (anonymous):
subtracted* typo
OpenStudy (anonymous):
23=L
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OpenStudy (aripotta):
yup. and since w = l - 7, and l = 23, we know that w = 23 - 7
OpenStudy (aripotta):
which would make w = ?
OpenStudy (anonymous):
for the length it is 23, but
about the width, being 16?
OpenStudy (aripotta):
yea, you're right. the length is 23, and the width is 16 :)
OpenStudy (anonymous):
ahh okay!!!thanks!!!
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OpenStudy (anonymous):
may i have a medal please?:)
OpenStudy (anonymous):
thanks lol:)