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Algebra 18 Online
OpenStudy (anonymous):

factor k^3 - 2k^2r - 3kr^2

OpenStudy (anonymous):

do you need help?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

what exactly r u trying 2 do

OpenStudy (anonymous):

trying to factor the trinomial

OpenStudy (anonymous):

k^3 - 2k^2r - 3kr^2

OpenStudy (anonymous):

okay hold please do u want me to explain how to do it or give u the answer

OpenStudy (anonymous):

how to do it and the answer

OpenStudy (anonymous):

okay hold on

OpenStudy (anonymous):

Okay im gonna scan something over to you that i think will help you and then ill send over the answer

OpenStudy (anonymous):

\[k ^{3}-2k ^{2}r-3kr ^{2}\] \[k(k ^{2}-2kr-3r ^{2})\] \[k(k ^{2} +kr-3kr-3r ^{2})\] \[k(k(k+r)-3r(k+r))\] \[k(k+r)(k-3r)\]

OpenStudy (anonymous):

Sorry I just got a new computer but i figured out how to scan scanning now

OpenStudy (anonymous):

page 1

OpenStudy (anonymous):

can someone explain step by step?

OpenStudy (anonymous):

how do you get -3kr?

OpenStudy (anonymous):

hey -2kr id there write.. i wrote it as 2 terms kr-3kr = -2kr

OpenStudy (anonymous):

oh

OpenStudy (anonymous):

OMG, THANK YOU SO MUCH i just figured it out

OpenStudy (anonymous):

@paigeyoung91 lol!

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