::::::::::::::: c program ::::::::::::::: #include void main() { int i=-0777; printf("%d",i); } explain why the output comes -551

Question

::::::::::::::: c program :::::::::::::::
#include<stdio.h>
void main()
{   
    int i=-0777;
    printf("%d",i);
}
explain why the output comes  -551

anonymous · Answer

decimal value of 777 is 511 how outcome is 551 can any one xplain clearly

anonymous · Answer

#include<stdio.h>
 int main()
 {
float i=1.0f,j=0.05f;
do
{
 printf("%.2f",i++ - ++j);
 }while(i<2.0 && j<=2.0);
 return 0;
 }

anonymous · Answer

http://www.wolframalpha.com/input/?i=octral+-777+as+decimal Somehow c is interpretting -0777 as an octal? Perhaps due to the leading 0.

espex · Answer

@wio is correct, to represent a hexadecimal value in your C or C++ code, you precede the number with a 0.

rsmith6559 · Answer

Octal has a leading zero.  Hex is 0x.