Question

How do I solve the log equation? 3 log 2x= 4

Answer 1

Standard operations. Several ways to go about it.

1) Divide by 3
2) Transform to Exponential Form.
3) Divide by 2

OR

1) Use log rules to move '3' inside the logarithm
2) Transform to Exponential Form.
3) Find the cube root.
4) Divide by 2

Pick a path that seem good to you,

Answer 2

log 2x=1.33.....log2+logx=1.33
hence find x..

Answer 3

Do we want a numerical answer with ambiguous rounding? \[x = \frac{1}{2}\cdot 10^{\frac{4}{3}}\] This is an exact answer.

Answer 4

Icame up with x=10.77 right?

Answer 5

10.772173450159418608796467832596 is closer. :-)

Good work. Let's see another one on your own.