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f(x) x^3-8/x^2-4 , x not equal to 2, X not equal to -2 3, x=2 4, x= -2 at which point is the function continuous?
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2 questions 1) is your equation\[f(x) = \frac{ x ^{3} - 8 }{ x ^{2} - 4 }\] with x not = 2 or -2? And 2) what do the second 2 lines mean? (3, x=2 and 4, x = -2)?
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