graphing inequalities pleae help
\[10x+30y \le1200\]
10x + 30y = 1200 x + 3y = 120 3y = -x + 120 y = (-1/3)x + 40 Can you graph this line?
kinda
not sure bout the negative
It is what is required of you to solve this type of problem. Give it a go.
do i just put a poin on (0,40)
and use 1 down n 3 across
rise over run
That's it. Since we have "less than or equal to", feel free to draw a solid line. Just draw the line. We can decide which side to shade, later.
im confused i got this question form this video tutorial from my cyberschool and the graph for 10x+30y=1200 isnt the same https://www.connexus.com/extra/ThirdPartyProviders/Pearson/Power_Algebra_2/MAT11NA_11_03_04_025/player.html
I can't see the video. You were not confused when your were talking about the slope and the intercept. How did the video discourage you?
no i understood what you said but the answer in the vid and your answer is different the video the video doesnt show how tograph it so i can explain
ima try to copy it down
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