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x^2 has positive co-efficient or negative ?
negative?
yes, negative
so the parabola would open upward or downward?
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downward
correct , now find x-intercept, can u ?
Not sure how
put f(x)=0 what u get ?
9?
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no thats not right .
0=-(x-3)^2 x-3=0 x=?
not sure
x-3=0 add 3 to both sides.
its c then!
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yes, but do u know why ?
cause i looked at my notes and i had it written down already >.> <.< ^_^
ok, here u get x-intercept = 3 so, your graph will 1)open downwards 2) will cut x axis at 3 and only graph c) satisfies it.
Yeah.. i was gonna say that
:p
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