What are the real or imaginary solutions of the polynomial equation?

x^3 = 216

–6, 3 + 3i *square root* 7, and 3-3i *square root* 7

–6, 3 + 3i *square root* 3, and 3-3i *square root* 3

6, 3 + 3i *square root* 7, and 3-3i *square root* 7

6, –3 + 3i *square root* 3, and -3-3i *square root* 3

Question

What are the real or imaginary solutions of the polynomial equation?

x^3 = 216 



–6, 3 + 3i *square root* 7, and 3-3i *square root* 7

–6, 3 + 3i *square root* 3, and 3-3i *square root* 3

6, 3 + 3i *square root* 7, and 3-3i *square root* 7

6, –3 + 3i *square root* 3, and -3-3i *square root* 3

cwrw238 · Answer

do you think the real solution is positive or negative?

anonymous · Answer

positive ?

cwrw238 · Answer

yes

cwrw238 · Answer

so its C or D

anonymous · Answer

so , it cant be the first two . .

cwrw238 · Answer

right

anonymous · Answer

c ?

cwrw238 · Answer

x^3 - 216 = (x - 6)(x^2 +12x + 36) = 0

use the quadratic formula to solve the  trinomial to get the 2 complex roots

cwrw238 · Answer

sorry the factors are
 (x - 6)(x^2 +6x + 36) = 0

cwrw238 · Answer

x = [-b +/- sqrt(b^2 - 4ac)]  / 2a