Question

How do I find the square root for the following equation?
dr=-4sin(t)*dt+3*dt+4cos(t)*dt

Answer 1

what do you mean?

Answer 2

How do I solve for dt

Answer 3

\[\int\limits dr =\int\limits -4\sin(t)*dt+\int\limits 3*dt+\int\limits 4\cos(t)*dt\]

Answer 4

4cos(t)+3x+4Sin(t)

Answer 5

r = 4cos(t)+3t+4sin(t) + c

Answer 6

why is my text getting sqrt13 as the answer?

Answer 7

go you have value for t?

Answer 8

0<=t<=3

Answer 9

Anyone?