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what are the zeros of P(x)=-3(x-2)(x+1)(x+i)(x-i)
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Umm.... did you do a mistake with i?
no, those are imaginary
Hint: set each factor equal to zero, then solve for x: x - 2 = 0 x + 1 = 0 x + i = 0 x - i = 0
thanks, i got that much.. but wasn't so sure
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