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Algebra
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what is the x intercept of y= –16x^2 + 210x
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Set y = 0 and solve for x
i dont no how can you explain ?
0 = -16x^2 + 210x Solve that
y=0, -16x^2+210x x(-16x+210) x=-210/-16
i got x=0, 105/8
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im assiming im wrong and @tasreeb is right
0 = -16x^2 + 210x 0 = -x(16x - 210) 0 = x(16x - 210) x = 0 16x - 210 = 0 16x = 210 x = 210/16 x = (0, 210/16)
so he was wrong also because his answers are negative, ?
-210/-16 = 210/16
-/- = +
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oh ya cause two negaties equal a positive lol sorry brain stub !
x=0, x=210/16
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