A system of two block with one frictionless pulley is release. Block one mass 3.00kg sitting on ground, block 2 mass 5.00 kg with a height of 4.00 meter. What is the velocity (speed) of the 5.0kg block in m/s when it strikes the ground. We have been using the conservation of momentum and Kinetic Energy (KE) and Potential Energy (PEg) formulas. ow do I set this up to solve?

Question

A system of two block with one frictionless pulley is release.  Block one mass 3.00kg sitting on ground, block 2 mass 5.00 kg with a height of 4.00 meter.  What is the velocity (speed) of the 5.0kg block in m/s when it strikes the ground.  We have been using the conservation of momentum and Kinetic Energy (KE) and Potential Energy (PEg) formulas.  ow do I set this up to solve?

anonymous · Answer

Since there's no energy lost in the system:
PE+KE before = PE + KE after
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