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find the sum of the series...
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\[\sum_{k=0}^{\infty} (4^{k}-3^{k})/5^{k}\]
sum of the geometric series with r=(4/5) minus the sum of the geometric series with r=(3/5)
what?
you haven't done geometric series?
I have but i dont understand it very well
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\[\sum_{ }^{ } (4/5)^k -\sum_{ }^{ } (3/5)^k \]
use the formula for the sum of a geometric series for each of those
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