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OpenStudy (anonymous):
calculus help! find the points of inflection and discuss the concavity of the graph of the function. f(x)=x(x-4)^2
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OpenStudy (anonymous):
Point of inflection is defined where the second derivative is zero. so take the derivative 2ce, set to zero and solve for x. \[f(x) = x^3-8x^2+16x\] \[f^{\prime} = 3x^2 -16x +16\] I will leave you to finish :)
OpenStudy (anonymous):
thanks.
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