Question

Anyone HW9?

Answer 1

ya got some answers of h9p1
.25
????
????
0
???
0
0
0

Answer 2

H9P1
0.25
7.5
7.5
0
HELP
0
0
0
H9P2
L*C
L/R
1
HELP
Help
(1/R)*sqrt(L/C)
HELP
H9P3
b/(2*m)
1/(sqrt(m*1/k))
1/(2*pi*sqrt(m*1/k))
(2*m)/(sqrt(m*(1/k)))

Answer 3

What formulas did you use for the 7.5 values? Thanks :)

Answer 4

0.5*L*I^2, because in this time the capacitor is full or consider a open circuit.

Answer 5

Thank you! Thank worked perfectly! Have a medal :)

Answer 6

LAB9
C = 126.5e-12
R = 25000

in the Fig2, change only D for 58% (H=2m, and C=1u)

Answer 7

@jose.oliveira2 can you show a picture as i dont understand the lab

Answer 8

becuase 58 % doent work for me when changin D so whats the formula please

Answer 9

lAB 9: FIRST ENTER ANSWERS C=126.5e-12,R=25000 AND THEN IN THE DIAGRAM WHERE YOU SEE PROPERTIES (square(0,3,30k,50),change value of 50 to 58.Then do a Transient analysis and click "check" button

Answer 10

And the H9P1 Q5 is -23.5619449019

the count is -L*2*pi*f*sin(2*pi*.f*t)
2*pi*f = w0

-15*2*pi*0.25*sin(2*pi*.25*5) = -23.5619449019

And the LAB is

Answer 11

thank you and can you say the formula for solving 2 and 3 as my variables are diffrent

Answer 12

H9P1
a) 0.250122093132
b) 7.5; the formula is 0.5*L*I^2, because capacitor is full
c) 7.5; the formula is 0.5*L*I^2, because in this time, consider the capacitor on open circuit
d) 0
e) -23.5619449019
f) 0
g) 0
h) 0

H9P2
a) L*C
b) L/R
c) 1
d) sqrt(1/(L*C))/(2*pi)
e) 1/(2*R*C)
f) (1/R)*sqrt(L/C)
g) 2*sqrt(L/C)

H9P3
a) b/(2*m)
b) 1/(sqrt(m*1/k))
c) 1/(2*pi*sqrt(m*1/k))
d) (2*m)/(sqrt(m*(1/k)))

Answer 13

Hi jose,
H9P2 f and g did not work with me? could you please help