Question

Give the equation y = x^2 - 4, what are the solutions to x^2 - 4 = 0 ?

Answer 1

\[(x+2)(x-2)=0\]

Answer 2

difference of two squares

Answer 3

How would you explain that is correct?

Answer 4

\[a^2-b^2=(a-b)(a+b)\]
so\[x=2,x=-2\]