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PLEASE HELP :) What is the range of the graph y=(x-4)^2+6.
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HINT: the graph of the equation is exactly like y=x^2 but translated 4 units to the right, 6 units up.
okay, i dont know how to right that though. i dont know how to solve for the range
someone please help. this is a live homework assignment and im timed and dont know how to reply to this
First, you have to figure out what the vertex is
your parabola is written in vertex form: \(\large y=a(x-h)^2+k \) where (h, k) is your vertex.
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okay so -4 and 6, how do i get the range from that
Actually its (h,k) = (4,6)
ok
Now all you have to do is figure out if the graph is concave up or concave down.
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