Question

solve for the indicated letter:
9/5C +32=F for C

Answer 1

\[{9\over5}C+32=F\]subtract 32 from both sides:\[{9\over5}C=F-32\]multiply both sides by the reciprocal of \(\large{9\over5}(\small{\text{which is } }\large{5\over9})\) to isolate C:\[C=(F-32){5\over9}\]distribute the fraction:\[C={{5F-160}\over9}\]

hope this explanation helps! :)

Answer 2

thank you ^^

Answer 3

anytime! :D