Question

Homework 9
Pt 1 (ii,iii & v)
Pt 2 (iv,v,vii) any help please

Answer 1

Question 1

2. 70
3. 70
5. -219.9

Question 2 didn't Complete please tell me answer of question 2 i,ii,iii,vi

Answer 2

if correct please click best response

Answer 3

H9P1
0.250122093132
7.5
7.5
0
-23.5619449019
0
0
0
H9P2
L*C
L/R
1
HELP
Help
(1/R)*sqrt(L/C)
HELP
H9P3
b/(2*m)
1/(sqrt(m*1/k))
1/(2*pi*sqrt(m*1/k))
(2*m)/(sqrt(m*(1/k)))

Answer 4

Reviwe

H9P1
a) 0.250122093132
b) 7.5
c) 7.5
d) 0
e) -23.5619449019
f) 0
g) 0
h) 0

H9P2
a) L*C
b) L/R
c) 1
d) sqrt(1/(L*C))/(2*pi)
e) 1/(2*R*C)
f) (1/R)*sqrt(L/C)
g) 2*sqrt(L/C)

H9P3
a) b/(2*m)
b) 1/(sqrt(m*1/k))
c) 1/(2*pi*sqrt(m*1/k))
d) (2*m)/(sqrt(m*(1/k)))

Answer 5

At the time just before the impulse happens what is the current iL(5.0−), in Amperes, through the inductor? Equation???

Answer 6

iL(t) = A*cos(2*pi*f*t) + B*sin(2*pi*f*t)
vC(t) = L*diL/dt = L*2*pi*f*(-A*sin(2*pi*f*t) + B * cos(2*pi*f*t))
The initial conditions mean that A = 1, and B = 0, (in my case)
So, iL (t) = cos(2*pi*f*t), vC (t) = -L*2*pi*f*sin(2*pi*f*t)
iL(5) = cos(2*pi*0.25*5) = cos(2.5*pi) = 0.

If you have another values, change only.

Answer 7

My Q No 1 (ii,iii & v) is not coming correct can anyone comment.

The current source puts out an impulse of area A=2/π=0.64 Coulombs at time t=5.0s.

At t=0 the state is: vC(0)=0.0 and iL(0)=1.0.

The equation governing the evolution of the inductor current in this circuit is

d2iL(t)dt2+1LCiL(t)=ALCδ(t−5.0)

(ii) At the initial time what is the total energy, in Joules, stored in the circuit?
(iii) At the time just before the impulse happens t=5.0− what is the total energy, in Joules, stored in the circuit?
(v) At the time just before the impulse happens what is the voltage vC(5.0−), in Volts, across the capacitor?

please comment...

Answer 8

Thats the same values and questions in my, i don´t know what happens.

Answer 9

try this

energy stored=½*L*iL^2 (b and c)
vC(t) = -L*2*pi*f*sin(2*pi*f*t) for (e)

Answer 10

@Jose.oliveira2 thanks brother its already done...thanks