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Need help in 5b (i)
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5b. fractional change = (Ls -Lo)/Lo =(Ls /Lo) -1 so than will be Lo =50 Ls =51,6 fractional change =(51,6 -50)/50 -1 = (1,6)/50 -1 = 0,032 -1 = - 0,968
so but what mean this (i) there in your question ?
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