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can someone teach me how to solve this?
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Area = ½*Base*Height. It's a right triangle. Base = x and Height = y. Almost done.
Use area = (1/2)bh where b is the base and h is the height of the triangle From the figure, you can see that base=x and height=y=x^2 So, the area = (1/2)(x)(y) = (1/2)(x)(x^2) = (1/2)x^3
how is the height x^2?
Do you see how the height is 'y'?
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oh yes my bad, i was looks at another problem that had different y value lol
this one has y=x^2 so the answer would be 1/2x^6?
How much is x*x^2?
wah no no this one has x^5 -.- sorry
Its okay :-)
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thank you
welcome :-)
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