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Pre-Algebra
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how do you solve 21-9x=-5(6x+3)-5(-4-4x)
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Use the distributive property to solve.
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Use parthkohli's advice
You first have to multiply the -5by (6x+3) and -5 by(-4-4x) Then add all like terms
-5 x 6, -5 x 3 ... -5 x -4, -5 x -4 ... So, it'd be 21-9x=-30x-15+20+20x. Add all the like terms: -9x+ (- 30x ) + 20x = 41x .. It would look like this: 21=-1x-20. Add 20 on both sides. (right side crosses out) 41=-1x. Divide -1 on both sides. X is left by itself..Answer: -41=x
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