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MIT 6.002 Circuits and Electronics, Spring 2007 16 Online
OpenStudy (anonymous):

VS=5.0V, VOH=3.5V, VIH=3.0V, VIL=0.9V, VOL=0.5V The gate-source capacitance CGS=3.5fF and VT=1.0V. RON=2100.0Ω, ROFF=115.0MΩ and RPU=12.0kΩ.

OpenStudy (anonymous):

my RON value was different so we will have different answers but the formula is as follow: for 2nd last part of h8p3: (-ln( (VOH-VS) / (VOL-VS) ) * (RPU+RON) * CGS) * 10^12 for last part of h8p3: (-ln( (VIL-(VS*RON/(RON+RPU))) / (VOH-(VS*RON/(RON+RPU))) ) * ((RON|| RPU) + RON) * CGS) * 10^12

OpenStudy (anonymous):

if you get the answers please give best response.

OpenStudy (anonymous):

tell me for above three h8p3

OpenStudy (anonymous):

@vndinesh h8p3 answers for a: 185.34 b: 5 c: 3.8

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