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Consider a quadratic equation (a+3) x2 + 2(1–a) x = –a + 1, has two different roots. Find the range values of a.
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has tow different roots so: 4(1-a)^2 - 4(a+3)(a-1) > 0 by solving this , you would find the range of a. tell me if u need more help.
the final answer is a<1
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