Question

I am clueless. 19yrs out of math. finding the x-intercepts of the parabola y=2x^2-4x

Answer 1

Use a graphing calculator.

Answer 2

you just need to factorise the quadratic by letting it equal zero, x intercepts occur where y = 0

so 0 = 2x^2 - 4x or 0 = 2x(x - 2)

so the values of x that make the equation true are x = 0 or x = 2

so these are the intercepts,.

Answer 3

hmmmm... where does (0,0) come into play...

Answer 4

its a point on the number plane where the parabola cuts the x axis