Quadrilateral ABCD has coordinates (3, 1), (4, 4), (7, 5), (6, 2). Quadrilateral ABCD is a

square because its length and width are both units and adjacent sides are perpendicular

rhombus because its length and width are both units and adjacent sides are not perpendicular

rectangle because its length is units, its width is units, and adjacent sides are perpendicular

trapezoid because it has only one pair of parallel sides

Question

Quadrilateral ABCD has coordinates (3, 1), (4, 4), (7, 5), (6, 2). Quadrilateral ABCD is a

 square because its length and width are both  units and adjacent sides are perpendicular

 rhombus because its length and width are both  units and adjacent sides are not perpendicular

 rectangle because its length is  units, its width is   units, and adjacent sides are perpendicular

 trapezoid because it has only one pair of parallel sides

anonymous · Answer

plot the points....and look at the figure...  just looking at the problem there are no right angles... so its a rhombus of trapezoid... find the distance between points... and it looks like square root 10...  

Hope this helps!