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f ' (x) = 2(2xsin(x)+x^2cos(x)) f ' (3)=?? Help please!
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i think you have to plug in the 3 in the x's of the function... so you set it up like f(3)=??????... yes... then solve and continue...
Yeah, but what about sin(3) and cos(3), there's no such thing.
f ' (x) = 2(2xsin(x)+x^2cos(x)) f'(3) = 2(2(3)sin(3)+3^2cos(3)) f'(3) =
There is a such thing sin(3) and cos(3)
oops... Thanks, I Hate MATH, too. Haha
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