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-6/7y-6≥42
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\[-\frac{6}{7}y-6 \ge 42\]?
\[-\frac{6}{7}y-6 \ge 42\] to \[-\frac{6}{7}y-6+6 \ge 42+6\] to \[-\frac{6}{7}y\frac{-7}{6} \le 48\frac{-7}{6}\] \[y \ge (9)(-7)\] \[y \le -63\]
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